Finding the Angle Phi in a Gravity-Affected System

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The discussion revolves around finding the angle phi in a gravity-affected system involving two masses, m and M, where m does not move relative to M. The user is attempting to analyze the forces acting on mass m, including gravitational force and tension, but is struggling with the relationship between the two masses and how to formulate motion equations. Participants suggest focusing on the forces acting parallel and perpendicular to the incline and applying Newton's laws to derive the acceleration of the system. The user expresses optimism about resolving the issue after considering the advice given. The conversation highlights the complexities of analyzing motion in a constrained gravitational system.
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Hello.
I have the attached problem.
The body whose mass is m doesn't move relative to the body M. Them both are affected only by gravity.
I need to find the angle phi.

Can anyone please help me?

http://img135.imageshack.us/img135/4690/1113169793tx6.gif"

Thank you.
 
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Show us what you've done so far and point out where you got stuck.

Hint: What's the motion of that contraption along the incline?
 
Doc Al said:
Show us what you've done so far and point out where you got stuck.

Hint: What's the motion of that contraption along the incline?

well, I tried to draw the forces on the little mass m, and I know the whole contraption is under a force (mgsin(alpha)), and I got to the point that on the little mass, I have the tension and the mg force and a d'elambert force to the left.
Im kinda stuck on doing that on the whole thing. I don't really know how to relate to the little mass in reference with the M mass, ie - I want to write the motion equations from the accelerating contraptions' POV, but then I don't know how to take the m mass's forces (should I take it as another force, ie mg+Mg=mgsinalpha, or not...).
 
D'alembertian forces? Let's have none of that crazy talk! :wink:

What's the acceleration of the contraption (and thus mass m)? Analyze forces parallel and perpendicular to the incline and apply good old Newton.
 
Thanks.
I think I got it... I'll try it and see how it turns out
:)
 
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