Finding the charge on a capacitor

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    Capacitor Charge
AI Thread Summary
To find the charge on the 32 μF capacitor, the relevant equation is Q = CV, where C is the capacitance and V is the voltage across the capacitor. The discussion highlights a misunderstanding regarding the charge distribution in series capacitors, emphasizing that the charge is the same across all capacitors in series, but the voltage may differ. The user initially calculated the total charge and divided it, which was incorrect. Clarification is sought on the potential difference between nodes c and d, which is crucial for determining the charge accurately. Understanding the charge distribution and voltage relationships in series connections is essential for solving the problem correctly.
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Homework Statement


http://screencast.com/t/B4865iOOLzX
What is the charge on the 32 μF centered-
upper capacitor?
Answer in units of μC


Homework Equations


Q = CV
1/c = 1/c1 + 1/c2...



The Attempt at a Solution


I found the charge across the entire thing and then divided that by 2, since the charge should be the same on all the plates. But that was wrong.
 
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What's the potential difference between nodes c and d?

What do you know about the charge distribution on capacitors connected in series?
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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