Finding the coefficient of Kinetic force with an angle

AI Thread Summary
A 1000N crate is pushed across a level floor at a constant speed by a 300N force at a 20-degree angle below the horizontal, leading to a question about calculating the coefficient of kinetic friction. The textbook solution indicates a coefficient of 0.256, but the user calculates 0.281, prompting confusion about the normal force. It is clarified that the normal force is not always equal to the weight of the object, as it can change based on additional forces acting on the crate. The discussion emphasizes the importance of drawing a free body diagram to identify all acting forces and accurately determine the normal force. Understanding these concepts is crucial for correctly solving the problem.
KellyTarzuoty
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Homework Statement


A 1000N crate is being pushes across a level floor at a constant speed by a force (F) of 300N at an angle of 20 degrees below the horizontal, what is the coefficient of kinetic force?

Homework Equations


Fk= uk*N
uk= Fk/N[/B]
Fk=F2

The Attempt at a Solution


in the back of the textbook it comes up as 0.256, but when I try I do:
Fk = F2
F2 = 300cos20 = 281.9
uk= F2/n
uk= 281.9/1000
uk= 0.281

Can someone tell me where I've gone wrong? It seemed like it should be a simple question
 
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The normal force from the ground is not always the weight of the object.
The normal force is what ever it needs to be to keep the block from accelerating vertically.
 
Nathanael said:
The normal force from the ground is not always the weight of the object.
The normal force is what ever it needs to be to keep the block from accelerating vertically.
okay, so should I try and use that to try and find the weight? Because that was all the question gave me, it didn't mention any weights.
 
KellyTarzuoty said:
okay, so should I try and use that to try and find the weight? Because that was all the question gave me, it didn't mention any weights.
The weight of the crate is given, it is 1000N.
In your equations you seem to be saying that the normal force is equal to the weight of the crate (1000N).

If I push down on a piece of paper, the normal force on the paper (from the table or whatever) is going to be much more than the weight of the paper, right?
 
Nathanael said:
The normal force from the ground is not always the weight of the object.
The normal force is what ever it needs to be to keep the block from accelerating vertically.
To be precise and general, the normal force from a surface is the force of least magnitude required to prevent the object penetrating the surface. Necessarily, that will be at right angles to the surface.

@KellyTarzuoty, draw a free body diagram of the block. Three forces act on it. What are they? Use the usual statics equations to find the normal force.
 
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