Finding the coefficient of kinetic friction of bricks

In summary: N force and F_N is the normal force on the brick (the vertical (upwards) force acting on the brick due to the floor the brick is resting on).So you can use this to figure out the (vertical) normal force F_N, and then use this to get the coefficient of kinetic friction \mu_k.In summary, to find the coefficient of kinetic friction acting on the brick, you need to calculate the normal force on the brick and then use it to determine the coefficient of kinetic friction using the equation Fkf = μk X FN.
  • #1
Skysong12
2
0

Homework Statement


A construction worker passes a brick to another worker by pushing it across a wooded floor. the brick has a mas of 2.7kg. The force required making the brick move with acceleration of 0.42m/s2 is 28 N. What is the co-efficient of kinetic friction acting on the brick?

The Attempt at a Solution



FN=Fg
= mass X acceleration
=2.7kg X 0.42m/s2
=1.134 N Fkf= μk X FN
μk = Fkf [itex]/[/itex] FN
= 28N [itex]/[/itex] 1.134N
=24.69

I'm pretty sure I got the acceleration part wrong. What am I supposed to do to find the normal force?
 
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  • #2
0.42 is the resultant acceleration so multiplying that by 2.7 kg will give you the resultant force.

28 N is the applied force, you are correct in that Fkf = μk X FN.

So what equation can you make to relate the 28 and Fkf ?

(Hint: A free body diagram will help you if you can't visualize it in your head)
 
  • #3
Skysong12 said:

Homework Statement


A construction worker passes a brick to another worker by pushing it across a wooded floor. the brick has a mas of 2.7kg. The force required making the brick move with acceleration of 0.42m/s2 is 28 N. What is the co-efficient of kinetic friction acting on the brick?



The Attempt at a Solution



FN=Fg
= mass X acceleration
=2.7kg X 0.42m/s2
=1.134 N


Fkf= μk X FN
μk = Fkf [itex]/[/itex] FN
= 28N [itex]/[/itex] 1.134N
=24.69

I'm pretty sure I got the acceleration part wrong. What am I supposed to do to find the normal force?

Hi Skysong12, welcome to Physics Forums.

The normal force for a mass M on a horizontal surface has magnitude M*g.

Where you started to calculate FN above you used the horizontal acceleration of the brick rather than g = 9.81 m/s2. So what you got instead of the normal force was the net horizontal force acting on the brick (the net horizontal force that results in the given acceleration of the brick of mass M).

The net horizontal force should also be equal to the difference between the applied force and the force due to friction: [itex] F_{net} = f_{applied} - \mu_k F_N [/itex]
 

1. What is the coefficient of kinetic friction?

The coefficient of kinetic friction is a measure of the amount of resistance between two surfaces in contact when one of the surfaces is moving relative to the other.

2. Why is it important to find the coefficient of kinetic friction of bricks?

The coefficient of kinetic friction is important because it helps us understand how much force is needed to move an object over a surface. In the case of bricks, this information can be useful for construction and engineering projects, as well as for predicting how objects will move on a brick surface.

3. How is the coefficient of kinetic friction of bricks measured?

The coefficient of kinetic friction can be measured by conducting an experiment where a brick is pulled across a surface at a constant speed and the force needed to maintain that speed is recorded. The coefficient of kinetic friction is then calculated by dividing the force by the weight of the brick.

4. What factors can affect the coefficient of kinetic friction of bricks?

The coefficient of kinetic friction can be affected by factors such as the type of surface the brick is moving on, the weight and shape of the brick, and the presence of any lubricants or contaminants on the surface.

5. How can the coefficient of kinetic friction of bricks be used in practical applications?

The coefficient of kinetic friction of bricks can be used in various practical applications, such as designing safe and efficient transportation systems for bricks, determining the slope and angle of surfaces for brick-laying, and predicting the movement of objects on brick surfaces in different environments.

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