Finding the indefinite integral

[csc2iffy]

Homework Statement

\int(x^(1/3)/(x^(1/3)+1))dx

Homework Equations

I know I have to use u substitution
u=x^(1/3)
du=1/(3x^(2/3))dx

The Attempt at a Solution

I know that the denominator of the equation will be u+1, but I don't understand how to find the numerator because I thought it would just be u, but wolfram alpha says it's u^3?

 

[Dick]

Homework Statement

\int(x^(1/3)/(x^(1/3)+1))dx

Homework Equations

I know I have to use u substitution
u=x^(1/3)
du=1/(3x^(2/3))dx

The Attempt at a Solution

I know that the denominator of the equation will be u+1, but I don't understand how to find the numerator because I thought it would just be u, but wolfram alpha says it's u^3?

If x^(1/3)=u then x^(2/3)=u^2. So du=(1/(3*u^2))dx. Does that tell you where the extra two powers of u are coming from?