Finding the magnitude of a magnetic field from a square loop

AI Thread Summary
To find the magnitude of the magnetic field at the center of a square loop carrying current, the discussion emphasizes using the Biot-Savart law. The initial approach involves calculating the magnetic field from a straight current-carrying wire, which can then be integrated for the four sides of the square loop. The proposed formula for the magnetic field from a straight wire is B = (μ₀I/4π)(L/x√(x²+(L/2)²)). The complexity arises from the square shape compared to a circular loop, which is noted to be simpler. The conversation highlights the importance of breaking the problem down into manageable parts to achieve the solution.
Patdon10
Messages
85
Reaction score
0

Homework Statement


A square loop, with sides of length L, carries current i. Find the magnitude of the magnetic field from the loop at the center of the loop, as a function of i and L. (Use any variable or symbol stated above along with the following as necessary: μ0.)


Homework Equations



magnetic field outside of a conductor:
u_0*I*r/A


The Attempt at a Solution



I got u_0*I*L/L^2

Not really sure what I should be doing differently? If it was in the shape of a circle it'd be easy, but because it's in a square, it's harder.
 
Physics news on Phys.org
I think the easiest way would be to try to solve the problem of finding the magnetic field produced by a straight current-carrying piece of wire of length L. Try to find the field at a point a distance x from the wire on its perpendicular bisector. You can do this by splitting the wire into infinitessimal lengths dl and then use the Biot and Savart law to calculate the field produced by dl. Then integrate along the length of the wire to find the total.

I think you should get

B = \frac{\mu_{0}I}{4\pi}\frac{L}{x\sqrt{x^{2}+(L/2)^{2} }}.
Now you've done the hard part it's just a matter of adding the fields from each of the 4 sides of the loop.
 
It seems pretty confusing, but I'll try it out and see what happens.
 
Patdon10 said:
It seems pretty confusing, but I'll try it out and see what happens.
I think that is the easiest way to do it. If you are trying to find the field from shapes like this then presumably you've covered the field from a straight current-carrying wire?

Patdon10 said:
If it was in the shape of a circle it'd be easy, but because it's in a square, it's harder.
How would you do it for a circle?
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top