Finding the mass of a ball and a rod using torque

AI Thread Summary
The discussion revolves around calculating the mass of a ball and a rod using torque, with a diagram depicting the setup. The user attempts to apply torque equations but encounters confusion due to a negative torque value for the ball's weight, despite having another torque acting in the same direction. Participants emphasize the need for clarity on the system's equilibrium and the directions of the applied forces, suggesting that the setup may not be in equilibrium without an upward force. The importance of a diagram is highlighted, as it could clarify the relationships between the forces and torques involved. The user struggles with uploading the diagram, which is essential for resolving the ambiguities in the problem.
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Homework Statement


There is a diagram of a rod with its center of mass labeled and a ball hanging down from it, attached by a string. Two torques are applied on either side. You are asked to find the mass of the ball and the mass of the rod.

Homework Equations


Torque = Force * Lever Arm * sine of angle between them

The Attempt at a Solution


I designated the center of mass of the rod as the axis, and then calculated the torque applied by each force by multiplying the magnitude of the force by the distance between where the force was applied and the center of mass of the rod. There is an angle of 60 degrees on the other side of where one force is being applied, so I calculated that the angle between the force and r (the lever arm, or distance from where that force is applied to the center of mass of the rod) is 120 degrees by subtracting 60 degrees from 180 degrees. What confuses me, though, is that, when I did my calculations, I got a negative value for the torque resulting from the ball's weight. I know torque can be negative, since it is a vector, but what confuses me about this result is that there is another torque that appears to be acting in the same direction as the one caused by the weight of the ball, yet it is positive. So I must have done something wrong. What is it?

Here are my calculations:

9N * 0.09m = 0.81 Nm

5.02N * sin120 degrees * 0.06m = 0.260846852 Nm

0.81 + Tball = 0.260846852

This is where I got the negative result.
 
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There's a lot of information missing here.
Physics Person said:
There is a diagram of a rod with its center of mass labeled and a ball hanging down from it, attached by a string. Two torques are applied on either side.
On either side of what? What direction are the torques? What do we know besides the fact that the torques are acting on it? Is this system in equilibrium? Where is the ball hanging relative to the center of mass? Where is the center of rotation relative to the center of mass and the ball?

Please attach a picture.
 
The two torques are applied on either end of the rod. It is not specified explicitly whether the system is equilibrium, but it appears to be in equilibrium from the picture. The torques appear to be pushing down on the rod. The ball is seven centimeters from the center of mass. You're supposed to treat a different position as the center of rotation, depending on whether you are trying to find the mass of the ball or the mass of the rod. When I was trying to find the mass of the ball, I treated the center of mass of the rod as the center of rotation. When I try to find the mass of the rod, I guess I'll just pick another point to be the center of rotation -- maybe where the ball is.
 
Physics Person said:
The torques appear to be pushing down on the rod.
Do you mean that two forces push down on the rod, and these will generate torques?
You describe a ball "hanging" from the rod, so I assume this is in a vertical plane and subject to gravity. Is there anything supporting the rod? Can't be in equilibrium if not!

Edit: maybe they are applied torques, not forces, but in that case it makes no sense to say they push down on the rod. They exert clockwise or anticlockwise torques. These could balance the torques produced by the weights of ball and rod, but still will not lead to equilibrium without an upward force somewhere.
 
to repeat @RPinPA ' s requst, please post the diagram. The question seems to be ambiguous without more details.
 
Yes, the rod is shown hanging from something else in the picture. Yes, the ball hanging from the rod is in a vertical plane and, I presume, therefore is subject to gravity. And the magnitudes of the applied forces are given in Newtons, hence why I referred to them as forces. They are forces that tend to cause a rotation. The one on the left seems like it would cause a counterclockwise rotation, whereas the one on the right seems like it would cause a clockwise rotation (assuming the axis of rotation to be the center of mass of the rod, which, in the picture, is shown to be pretty much right smack-dab in the center of the rod).
 
Physics Person said:
Yes, the rod is shown hanging from something else in the picture. Yes, the ball hanging from the rod is in a vertical plane and, I presume, therefore is subject to gravity. And the magnitudes of the applied forces are given in Newtons, hence why I referred to them as forces. They are forces that tend to cause a rotation. The one on the left seems like it would cause a counterclockwise rotation, whereas the one on the right seems like it would cause a clockwise rotation (assuming the axis of rotation to be the center of mass of the rod, which, in the picture, is shown to be pretty much right smack-dab in the center of the rod).
If there is a single support in the centre of the rod, providing an unknown upward force, it will be impossible to find the mass of the rod.
I can't see that we will get very far with this until you attach an image of the problem as given to you.
 
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haruspex said:
If there is a single support in the centre of the rod, providing an unknown upward force, it will be impossible to find the mass of the rod.
I can't see that we will get very far with this until you attach an image of the problem as given to you.

I cannot figure out how to insert an image, since, when I click on the image icon when I am typing out my reply, it asks for the URL of the image, and I do not have the image uploaded to any website, but instead have it saved among the images on my phone.
 
Physics Person said:
I cannot figure out how to insert an image, since, when I click on the image icon when I am typing out my reply, it asks for the URL of the image, and I do not have the image uploaded to any website, but instead have it saved among the images on my phone.
See the UPLOAD button, lower right.
 
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