Finding the mininum value of the coffecitent of friction

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The discussion focuses on a physics problem involving a 1.0 kg hanging mass and a 4.0 kg block on a table, specifically calculating the acceleration and the minimum coefficient of static friction required for the block to remain stationary. For part a, the coefficient of kinetic friction is given as 0.2, leading to an acceleration of 2 m/s² after calculating the frictional force. For part b, determining the minimum static friction coefficient requires analyzing the system as a whole, using the equation F = ma to relate gravitational and frictional forces. The conversation emphasizes the importance of correctly applying fundamental physics equations to solve the problem. Understanding the dynamics of both blocks is crucial for finding the solution.
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Homework Statement



1. Suppose a hanging 1.0kg lab mass is attached to a 4.0kg block on the table

(The picture)

lpZkr.jpg


a. If the coefficient of kinetic friction, \muk is .2, what is the acceleration?

b. What would the mininum value of the coefficient of static friction, \mus, in order for the block to remian motionless

Homework Equations



a = f/m
\mu = frictional force / normal force

The Attempt at a Solution



a) .2 = friction/50 (i got 50 from 5 [the two blocks] multiplied by gravity)... friction = 10
a = 10/5
a = 2m/s

b) idk how to figure this out?
 
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You need to look at both blocks as a system.

Friction Force due to gravity on the hanging block.
<------------------(mass of both blocks)----------------------------------------------->

Keep in mind that a=f/m isn't really an equation. F=ma is the sum of all forces on an object or system. With that being said you can now use that equation as follows:

F=ma
Fg-Ff=ma...and I'm sure you can finish the rest.
 
i meant

a = \Sigmaf / m

thats a real equation
 

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