Finding the speed of a proton in a mass spectrometer

AI Thread Summary
A mass spectrometer deflects charged particles using magnetic or electric fields. The problem involves calculating the speed of a proton starting from rest at a potential of 10,000 V, with a mass of 1.67x10^-27 kg and a charge of 1.6x10^-19 C. The radius of curvature of the proton's path is given as 3.00 m. The discussion emphasizes the importance of understanding the principles of mass spectrometry to solve the problem effectively. After reviewing relevant resources, the original poster was able to find the solution.
Mack199
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Homework Statement


A mass spectrometer uses either a magnetic field or an electric field to deflect charged particles.

A proton starts from rest a plate P. The Speed of the proton as it passes through the hole in plate Q is?

V= 10000 V
Mass of a proton = 1.67x10^-27
Charge of a proton = 1.6x10^-19

With this you then need to find the magnetic field intensity.

Radius of curvature of a protons path is 3.00 m.

Homework Equations



I have no clue?

The Attempt at a Solution



Dont know were to start?
 
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Thanks for the help. After reading over that i was able to awnser the question.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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