Finite quantum well, multiple choice question

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SUMMARY

The minimum possible kinetic energy of an electron trapped in a one-dimensional finite quantum well of width L is exactly h²/8mL². This conclusion is derived from the energy equation E=n²*h²/8mL², specifically for the ground state (n=1). The uncertainty principle confirms that if the kinetic energy were zero, the position uncertainty would be infinite, which contradicts the requirement for the electron to be confined within the well. Therefore, the correct answer is D) Exactly h²/8mL².

PREREQUISITES
  • Understanding of quantum mechanics principles, particularly the uncertainty principle.
  • Familiarity with the concept of finite quantum wells and their energy states.
  • Knowledge of the energy quantization formula E=n²*h²/8mL².
  • Basic grasp of non-relativistic quantum mechanics.
NEXT STEPS
  • Study the implications of the uncertainty principle in quantum mechanics.
  • Explore the derivation and applications of the finite quantum well model.
  • Learn about energy quantization in different quantum systems.
  • Investigate the differences between relativistic and non-relativistic quantum mechanics.
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Students of quantum mechanics, physics educators, and anyone interested in the principles of quantum confinement and energy quantization.

Theodore0101
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Homework Statement
Consider an electron trapped in a one-dimensional finite well of width L. What is the minimum possible kinetic energy of the electron?

A) 0

B) Between 0 and h^2/8mL^2

C) ≈h^2/8mL^2, but it is not possible to find the exact value because of the uncertainty principle

D) Exactly h^2/8mL^2
Relevant Equations
E=n^2 *h^2/8mL^2
Homework Statement:: Consider an electron trapped in a one-dimensional finite well of width L. What is the minimum possible kinetic energy of the electron?

A) 0

B) Between 0 and h^2/8mL^2

C) ≈h^2/8mL^2, but it is not possible to find the exact value because of the uncertainty principle

D) Exactly h^2/8mL^2
Homework Equations:: E=n^2 *h^2/8mL^2

Hi!

I think I can rule out A) since if there is no kinetic energy the velocity must be 0, therefor there is no momentum, and then no uncertainty of momentum. Because of the uncertainty principle the uncertainty of position would therefor be infinitive, and we require the electron to be within L, so that wouldn't work.

I know that the lowest energy has something to do with h^2/8mL^2 since that's what the state n=1 gives, but all of the remaining options have a connection to it and I'm not sure from here.

Thanks
 
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Hint:
An alternate question: What is minimum possible energy of electron in the box? Can you answer this?
 
Abhishek11235 said:
Hint:
An alternate question: What is minimum possible energy of electron in the box? Can you answer this?

The least amount of energy it can have is h^2/8mL^2, right? Is all the energy kinetic energy? Is that the answer?
 
Yes. This is the minimum kinetic energy the particle can possess(If you work in the realm of non relativistic QM
 

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