grscott_2000
- 48
- 0
Question solved
Last edited:
No, if the diameter of the pipe is .6 m then its radius is .6/2= .3 m.grscott_2000 said:The problem..
I have been given a flow rate in units of m^3 per second. I also know the diameter of the pipe the fluid is flowing in meters.
I have to calculate the velocity of the flow and give the answer in units of ms^-1
Relevant values..
pipe diameter = 0.6m
flow rate = 5 m^3 per second
My answer...
I know that
flow rate = cross sectional area x velocity
So all things considered I should just be able to rearrange the equation to give
velocity = flow rate / area = 5 / (pi * .15 * .15) = 70.7 ms-1
Yes, this is exactly the same thing: diameter= 2*radius so (diameter)^2= 4*radius. Canceling the "4" in the numerator and denominator gives exactly what you have above.Second point...
I also know that
velocity = 4 * flow rate / (pi * (pipe diameter)^2)
Although you have the correct answer, there is a typo on the left: "pi" should not be squared.Which gives a completely different answer...
(4 * 5) / ((pi * 0.6)^2) = 17.68 ms-1
I would very much appreciate anyone who can help me out with this apparent annomily. I tend to think that the second point is correct because I can plug various values into it, rearrange etc and still get a sensible answer