Flow Rate & Velocity: Solution Found

AI Thread Summary
The discussion centers on calculating the velocity of fluid flow given a flow rate of 5 m³/s and a pipe diameter of 0.6 m. The initial calculation incorrectly used the radius of 0.15 m instead of the correct radius of 0.3 m, leading to an erroneous velocity of 70.7 m/s. The correct formula for velocity, derived from the flow rate and cross-sectional area, yields a velocity of approximately 17.68 m/s when using the diameter directly. A clarification was made regarding a typo in the formula, emphasizing that "pi" should not be squared. The consensus is that the second calculation method is accurate and consistent with expected results.
grscott_2000
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grscott_2000 said:
The problem..
I have been given a flow rate in units of m^3 per second. I also know the diameter of the pipe the fluid is flowing in meters.

I have to calculate the velocity of the flow and give the answer in units of ms^-1


Relevant values..
pipe diameter = 0.6m
flow rate = 5 m^3 per second


My answer...

I know that

flow rate = cross sectional area x velocity

So all things considered I should just be able to rearrange the equation to give

velocity = flow rate / area = 5 / (pi * .15 * .15) = 70.7 ms-1
No, if the diameter of the pipe is .6 m then its radius is .6/2= .3 m.

You should have 5/(pi* .3* .3)= 17.7 m/s.



Second point...

I also know that

velocity = 4 * flow rate / (pi * (pipe diameter)^2)
Yes, this is exactly the same thing: diameter= 2*radius so (diameter)^2= 4*radius. Canceling the "4" in the numerator and denominator gives exactly what you have above.

Which gives a completely different answer...

(4 * 5) / ((pi * 0.6)^2) = 17.68 ms-1
Although you have the correct answer, there is a typo on the left: "pi" should not be squared.

I would very much appreciate anyone who can help me out with this apparent annomily. I tend to think that the second point is correct because I can plug various values into it, rearrange etc and still get a sensible answer
 
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