(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

a 4mm hole is 1m below the surface of 2m diameter water tank.

a.what is the volume flow rate through the hole in L/min?

b.what is the rate in mm/min at which the water level in the tank will drop if the water is not replenished.

[PLAIN]http://i285.photobucket.com/albums/ll55/tebsa08/tank.jpg[/PLAIN]

2. Relevant equations

Q=vA

v1A1=v2A2

V1=A1[tex]\Delta[/tex](x1)=v1A1[tex]\Delta[/tex](t)

V2=A2[tex]\Delta[/tex](x2)=v2A2[tex]\Delta[/tex](t)

p+.5[tex]\rho[/tex]v1^2+[tex]\rho[/tex]gy=constant

3. The attempt at a solution

a. A1=[tex]\pi[/tex]r^2=[tex]\pi[/tex]*1^2=3.14m^2, A2=[tex]\pi[/tex]r^2=[tex]\pi[/tex]*.002^2=1.25x10^-5m^2

im sorry i really dont understand fluid dynamics, i have no idea how to find v, to get Q... ans part b, i dont even undestand the question.... plz someone help me,

can i find v by, [tex]\rho[/tex]+[tex]\rho[/tex]gy=[tex]\rho[/tex]+.5[tex]\rho[/tex]v^2

and all the densities cancel so v=[tex]\sqrt{}2gy[/tex]???

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# Homework Help: Fluid Dynamics Flow Rate

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