thelovemonkey
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hey guys I am new to the forum... i am a first year civil engineering student trying to do a second year course over this summer holiday. for fluid mechanics i was given this h/w problem. could you please tell me if I am correct and if not make explain where i went wrong and how to correct it?
at 25 C a fluid has an absolute viscosity of 0.0978 Poise and a Specific Gravity of 0.997. Compute:
a. absolute viscosity in Ns/m^2
b. Kinematic viscosity in SI units
Specific Gravity(SG)= Density of substance(Ds)/ Density of Water(Dw)
Kinematic Viscosity (KV) = Absolute Viscosity in SI units/ Density of Substance(Ds)
1 Poise= 0.1 Ns/m^2
A.
if
1 Poise= 0.1 Ns/m^2
then
o.00978 Poise = 0.1 x 0.00978 Ns/m^2 = 0.000978 Ns/m^2
B.
KV= Abs. Viscosity/ Ds
SG= Ds/Dw
Ds= SG x Dw = 1000 kg/m^3 x 0.997 = 997kg/m^3
KV = (0.000978 Ns/m^2)/ (997 kg/m3)
=> KV= 9.8 x 10^-7 Nsm/Kg
Homework Statement
at 25 C a fluid has an absolute viscosity of 0.0978 Poise and a Specific Gravity of 0.997. Compute:
a. absolute viscosity in Ns/m^2
b. Kinematic viscosity in SI units
Homework Equations
Specific Gravity(SG)= Density of substance(Ds)/ Density of Water(Dw)
Kinematic Viscosity (KV) = Absolute Viscosity in SI units/ Density of Substance(Ds)
1 Poise= 0.1 Ns/m^2
The Attempt at a Solution
A.
if
1 Poise= 0.1 Ns/m^2
then
o.00978 Poise = 0.1 x 0.00978 Ns/m^2 = 0.000978 Ns/m^2
B.
KV= Abs. Viscosity/ Ds
SG= Ds/Dw
Ds= SG x Dw = 1000 kg/m^3 x 0.997 = 997kg/m^3
KV = (0.000978 Ns/m^2)/ (997 kg/m3)
=> KV= 9.8 x 10^-7 Nsm/Kg