Fluid Mechanics Question: Calculation of kinematic velocity

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SUMMARY

The discussion centers on calculating kinematic velocity in fluid mechanics, specifically for a fluid with an absolute viscosity of 0.0978 Poise and a specific gravity of 0.997 at 25°C. The absolute viscosity was correctly converted to SI units as 0.000978 Ns/m². The kinematic viscosity was calculated using the formula KV = Absolute Viscosity / Density of Substance, resulting in a kinematic viscosity of 9.8 x 10^-7 Nsm/Kg. The calculations and methodology presented were confirmed as correct by peers in the forum.

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hey guys I am new to the forum... i am a first year civil engineering student trying to do a second year course over this summer holiday. for fluid mechanics i was given this h/w problem. could you please tell me if I am correct and if not make explain where i went wrong and how to correct it?



Homework Statement


at 25 C a fluid has an absolute viscosity of 0.0978 Poise and a Specific Gravity of 0.997. Compute:
a. absolute viscosity in Ns/m^2
b. Kinematic viscosity in SI units


Homework Equations



Specific Gravity(SG)= Density of substance(Ds)/ Density of Water(Dw)

Kinematic Viscosity (KV) = Absolute Viscosity in SI units/ Density of Substance(Ds)

1 Poise= 0.1 Ns/m^2


The Attempt at a Solution




A.
if
1 Poise= 0.1 Ns/m^2

then

o.00978 Poise = 0.1 x 0.00978 Ns/m^2 = 0.000978 Ns/m^2


B.

KV= Abs. Viscosity/ Ds

SG= Ds/Dw

Ds= SG x Dw = 1000 kg/m^3 x 0.997 = 997kg/m^3


KV = (0.000978 Ns/m^2)/ (997 kg/m3)

=> KV= 9.8 x 10^-7 Nsm/Kg
 
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Yes your work is correct.
 
the lecturer showed us a pretty neat way to handle these units...

Nsm/Kg ->

since N= Kg/m^2
then

units = m^2/ S


very late don't have time to rbeak down
 

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