Force and acceleration question

  • Thread starter Thread starter physics_geek
  • Start date Start date
  • Tags Tags
    Acceleration Force
AI Thread Summary
A force applied to two objects of different masses results in different accelerations, with the first object (m1) accelerating at 3.20 m/s² and the second (m2) at 1.00 m/s². The ratio of their masses is calculated to be 0.313. When combining m1 and m2, the acceleration under the same force F will decrease due to the increased total mass. The key to solving part b is recognizing that the acceleration can be found using the combined mass of m1 and m2. The discussion concludes with the participant successfully understanding how to calculate the new acceleration.
physics_geek
Messages
82
Reaction score
0

Homework Statement


A force F applied to an object of mass m1 produces an acceleration of 3.20 m/s2. The same force applied to a second object of mass m2 produces an acceleration of 1.00 m/s2.
(a) What is the value of the ratio m1/m2?


(b) If m1 and m2 are combined, find their acceleration under the action of the force F.


Homework Equations


f=ma m1a1=m2a2


The Attempt at a Solution


i figured the out part a...the ratio to m1 to m2 is .313

i don't understand part b..i know if you add m1 and m2..the resulting acceleration should be smaller
 
Physics news on Phys.org
physics_geek said:
A force F applied to an object of mass m1 produces an acceleration of 3.20 m/s2. The same force applied to a second object of mass m2 produces an acceleration of 1.00 m/s2.
(b) If m1 and m2 are combined, find their acceleration under the action of the force F.

i don't understand part b..i know if you add m1 and m2..the resulting acceleration should be smaller

Hi physics_geek! :smile:

It just means what is the acceleration if the same F acts on a mass of (m1 +m2)
 
k thnx
figured it out!
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top