Force & Motion: Find Force Values for 600g Object

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The discussion revolves around calculating force values for a 600 g object using the formula F=MA. Initially, the user incorrectly multiplied the mass by 5 and 10, resulting in values of 3000N and 6000N. After troubleshooting, they realized the mass should be converted to kilograms, leading to the correct multiplication by 0.6 instead of 600. This adjustment clarified the calculations, and the user expressed confidence in resolving the issue. The thread highlights the importance of unit conversion in physics problems.
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Homework Statement


What force values go in the blanks on the horizontal scale?
The figure (attached as an image) shows an acceleration-versus-force graph for a 600 g object.

Homework Equations



F=MA


The Attempt at a Solution



I was thinking from F=ma that:
a) F=5X600 = 3000N
b) F=10X600 = 6000N

But my answer is definitely not being accepted by the computer so i must be doing something wrong. Any ideas?
 

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I got it... =)

After much trial and error i realized it. Its in Grams should i should have been multiplying by 0.6 NOT 600

I'm sure i'll be back here soon though. Thanks!
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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