Can someone tell me if I'm right? 0.98 seems a bit high for the coefficient of friction? A 25kg sled is pulled at a steady 1.3 m/s by a rope inclined 40 degrees above horizontal. If the pulling force is 26.7 N, what is the coefficient of friction between the sled runners and the snow? m = 25 kg, v = 1.3 m/s, Fp = 26.7 N, mgcos40 = Fn = 187.7 N, Ftotal = ma (Ftotal = 0 because of no acceleration). Fp + mgsin40 - Ff = 0, 26.7 + 157.5 = Ff, Ff = 184.2. u = Ff/Fn = 184.2/187.7 = 0.98.