Forces between 2 parallel wires=>

AI Thread Summary
The discussion revolves around calculating the magnetic field (B) at the center of a square formed by four parallel wires carrying equal currents. The user initially attempts to apply the Biot-Savart law but struggles to find the correct answer. Guidance is provided regarding the symmetry of the setup, suggesting that the magnetic fields from opposite wires may cancel each other out. The user expresses gratitude for the insights and requests the final answer to the problem. The conversation highlights the importance of understanding magnetic field interactions in symmetrical arrangements.
noobie!
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Homework Statement


four long straight parallel wires located at the corners of a square of side l=6cm carry equal current I=10A which is perpendicular.Determine the magnitude and direction of B at the center of the square.

Homework Equations


don't have,so sorry..


The Attempt at a Solution


i begin with drawing a free body diagram where the forces are located.Then i resolve them according to y-axis and x-axis.i use B=u(Ia)(Ib)l / 2pie(r) correct me if I'm wrong,but somehow i can't get the ans..could you please kindly rectify and guide me..thanks a lot..=>:smile:
 
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noobie! said:

Homework Statement


four long straight parallel wires located at the corners of a square of side l=6cm carry equal current I=10A which is perpendicular.Determine the magnitude and direction of B at the center of the square.

Homework Equations


don't have,so sorry..

The Attempt at a Solution


i begin with drawing a free body diagram where the forces are located.Then i resolve them according to y-axis and x-axis.i use B=u(Ia)(Ib)l / 2pie(r) correct me if I'm wrong,but somehow i can't get the ans..could you please kindly rectify and guide me..thanks a lot..=>:smile:

Are there any symmetries that you think you can exploit?
Such as what are the directions of the B-field at the center point. Do any of them offset each other?
 
oh,i can figure it out already,thanks for your guidance o:)
 
Could you please post the answer?
I subscribed to this thread to see the answer :P
 
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