Forces on a Skydiver during the initial frefall phase of the jump

AI Thread Summary
During the initial freefall phase of a skydiver’s jump, the air resistance is 251N, and the acceleration is 5.96 m/s² downward. To calculate the mass of the skydiver, the net force equation can be expressed as Fnet = weight - air resistance. The weight is calculated using the gravitational acceleration of 9.8 m/s², leading to the equation 251N = m(5.96 m/s² + 9.8 m/s²). Solving this gives a mass of approximately 65.36 kg for the skydiver. Understanding these forces is crucial for analyzing the dynamics of freefall.
Balsam
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Homework Statement


A skydiver is jumping out of an airplane. During the first few seconds of one jump, the parachute is unopened, and the magnitude of the air resistance acting on the skydiver is 251N. The acceleration of the skydiver during this time is 5.96 m/s^2 [down]. Calculate the mass of the skydiver.
g=9.8 m/s^2[down]
air resistance=251N[up]
acceleration=5.96m/s^2 [down]

Homework Equations


Fnet=ma
Fg=mg

The Attempt at a Solution


[/B]
I drew a diagram and have plugged in the known variables to each equation. For Fg=mg-- Fg=m(9.8m/s^2[down])

for F=ma-- Fnet=m(5.96 m/s^2[down]).

for Fnet--Fnet= 251N[up] + m(9.8 m/s^2 [down]) x 5.96 m/s^2[down].

I'm stuck here, I don't know how to solve for mass from here.
 
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Balsam said:

Homework Statement


A skydiver is jumping out of an airplane. During the first few seconds of one jump, the parachute is unopened, and the magnitude of the air resistance acting on the skydiver is 251N. The acceleration of the skydiver during this time is 5.96 m/s^2 [down]. Calculate the mass of the skydiver.
g=9.8 m/s^2[down]
air resistance=251N[up]
acceleration=5.96m/s^2 [down]

Homework Equations


Fnet=ma
Fg=mg

The Attempt at a Solution



I drew a diagram and have plugged in the known variables to each equation. For Fg=mg-- Fg=m(9.8m/s^2[down])

for F=ma-- Fnet=m(5.96 m/s^2[down]).[/B]

for Fnet--Fnet= 251N[up] + m(9.8 m/s^2 [down]) x 5.96 m/s^2[down].

I'm stuck here, I don't know how to solve for mass from here.
You should draw a free body diagram of the skydiver and label the forces acting on his body while he's falling. Then, write your equation for Fnet.
 
SteamKing said:
You should draw a free body diagram of the skydiver and label the forces acting on his body while he's falling. Then, write your equation for Fnet.

I did. I assume the only forces are air resistance and gravity and i came to the conclusion that Fg must be greater than 251N (in terms of magnitude) for the person to be falling.
 
Balsam said:
I did. I assume the only forces are air resistance and gravity and i came to the conclusion that Fg must be greater than 251N (in terms of magnitude) for the person to be falling.
The way you wrote the equation for Fnet in the OP is confusing. Try expressing Fnet in terms of the weight of the skydiver and the drag force. Don't include the net acceleration just yet.
 
Fnet=251N-mg=ma
251N=ma+mg
251N=m(a+g)
251N=m(-5.96m/s/s+9.8m/s/s)
251N=m(3.89m/s/s)
251N/(3.89m/s/s)=m
65.36kg=m
 
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