A particle is release from rest (y=0) and falls under the influence of gravity and air resistance. Find the relationship between v and the distance of falling y when the air resistance is equal to (a) αv and (b) βv²
The Attempt at a Solution
Setting the origin at the point from where the particle is released, with y pointing downwards, we have, from F=ma, that dv/dt=g-αv, hence ∫dv=∫(g-αv)dt, so, as vdt=dy, v=gt-αy.
Is it right so far? How do I eliminate the time depence? The solution manual has a very different approach that I did not understand, so it may be possible that my attempt won't get me to the answer. Thanks