What Is the Beat Frequency Between Two Close Tuning Fork Frequencies?

  • Thread starter Thread starter sonutulsiani
  • Start date Start date
  • Tags Tags
    Frequency Tuning
AI Thread Summary
The discussion centers on calculating the beat frequency between two tuning forks with frequencies of 256 Hz and 258 Hz. The correct beat frequency is determined to be 2 Hz, which is the difference between the two frequencies. Participants note that while 2 Hz is the calculated beat frequency, it is not audible to the human ear. The consensus is that the only logical answer is 2 Hz, despite the fact that it falls below the audible range. The conversation highlights the nature of beat frequencies and their calculation.
sonutulsiani
Messages
136
Reaction score
0

Homework Statement



Two tuning forks are struck and the sounds from each reach your ears at the same time. One sound has a frequency of 256 Hz, and the second sound has a frequency of 258 Hz. The underlying "hum" frequency that you hear is:
A. 2 Hz
B. 256 Hz
C. 258 Hz
D. 257 Hz

Homework Equations


The Attempt at a Solution



I got it as 2 HZ
 
Physics news on Phys.org
Probably. Computer generated question?

The hesitation is because no one can hear 2 Hz.
 
Nah homework question!
 
Is it 2HZ?
 
yes, but I agree with Delphi--two hz is not audible. Beat frequencies are generated by sums and differences of the fundamentals. The only choice which makes sense is 2.
 

Thread 'Struggling to understand the concept of this question (ice cube in water optics question)'

TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
View full post »
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
View full post »

Similar threads

Solving Beat Frequency with Tuning Forks: f2 = f1 ± fb
Replies
6
Views
5K
Guitar Strings & Tuning Forks: Investigating Beats
Replies
4
Views
2K
What Is the Frequency of Tuning Fork B When Tuned with Wax If A Is 212 Hz?
Replies
22
Views
5K
What is the period of the loaded tuning fork?
Replies
4
Views
4K
What Was the Initial Frequency of the Trumpet Player?
Replies
2
Views
5K
How to find the wavelength of the sound of the tuning fork?
Replies
15
Views
9K
Beat frequency heard from two tuning forks
Replies
4
Views
3K
Doppler effect and beat frequency
Replies
3
Views
2K
Beats calculation/Doppler Effect
Replies
1
Views
2K
Flute player initial frequency?
Replies
7
Views
8K

Hot Threads

Recent Insights

Back
Top