Frequency of X-Rays: Calculate from Wavelength to GHz

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To calculate the frequency of X-rays from their wavelength, the formula used is wavelength multiplied by frequency equals the speed of light (c). Given a wavelength of 0.126 nm, the correct approach involves using the speed of light, approximately 3 x 10^8 m/s, to find the frequency in Hz. The initial calculation of 7936507937 Hz converts to approximately 7.94 GHz, but the user indicates this result is incorrect. The confusion arises from the understanding of the relationship between wavelength and frequency; they are inversely related, and using the correct speed of light is essential for accurate calculations. Thus, the correct frequency can be confirmed by ensuring the proper use of the speed of light in the formula.
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Homework Statement


X-rays are electromagnetic waves with very short wavelengths. Suppose an X-ray has an wavelength of 0.126 nm. What is its frequency?

The Attempt at a Solution


I tried (1)/(1.26E-10)=7936507937, which is in Hz, but they want it to GHz, so i converted it and got 7.94 GHz but it's incorrect? Any idea where I'm going wrong?
 
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Wavelength is not the inverse of frequency.

wavelength x frequency = speed
 
Chi Meson said:
Wavelength is not the inverse of frequency.

wavelength x frequency = speed

So what is the speed? Is it the constant c, 3E8? And will using that give me my answer in Hz?
 
yes its c, all EM radiations have speed c
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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