(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Two blocks (m1 and m2) are being pushed to the right along a frictionless table with such a force that the left block (m1), which is smaller, is above the table and not falling. It is pushed up against m2 (which is on the table), and they have a coefficient of static friction of 0.4 between them. The mass of m1 is 16 kg and m2 is 80 kg. What is the minimum applied force from the left required to keep m1 from sliding down m2?

2. Relevant equations

f_{s}≤u_{s}F_{normal}

F_{net}=ma

3. The attempt at a solution

I drew a force body diagram and found that since there is no vertical movement for m1, the net force is zero so the downward weight force must cancel with the upward frictional force of m2 on m1. Since the weight = 156.96 N, the frictional force must also. This is set equal to 0.4F_{normal}to find that the minimum normal force required is equal to 392.4 N. Since this force acts opposite to the applied force, the applied force must be greater than or equal to this number. However, the system is not accepting my answer of 392.4 N. Can anyone point out to me what I did wrong?

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# Homework Help: Friction in vertical directions

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