Friction of a car going in circles

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SUMMARY

The discussion focuses on calculating the acceleration and friction force of a car weighing 900 kilograms, traveling at a constant speed of 110 km/h on a racetrack with a radius of 100 meters. The correct acceleration is determined to be 9.34 m/s² using the formula a = v² / r. However, the friction force calculation of 8.65 kN is incorrect; the correct approach involves using the kinetic friction formula fk = μk * n, where μk is the friction coefficient (0.980) and n is the normal force (weight of the car). The accurate friction force should be calculated as 8.82 kN.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with circular motion concepts
  • Knowledge of friction coefficients and their applications
  • Proficiency in basic algebra and equation manipulation
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  • Review the principles of circular motion and centripetal acceleration
  • Study the calculations for normal force in different scenarios
  • Learn about the implications of friction coefficients in vehicle dynamics
  • Explore advanced topics in dynamics, such as the effects of varying speeds on friction
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Physics students, automotive engineers, and anyone interested in the dynamics of vehicles on curved paths will benefit from this discussion.

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Homework Statement


A car that weighs 900 kilograms is driving around a racetrack, the radius of the racetrack is 100 meters. Thecar has a constant speed of 110 km/h. The friction coefficient between the tires and the track is 0.980.

Decide:

a) The car's acceleration
b) The size of the friction

Homework Equations


The Attempt at a Solution



I got a to 9.34 m/s2 which I believe is correct. I'm having a much harder time with b which I get to 8,65 kN which I know is incorrect.Please help! Thanks!
 
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could you show some equations you found
 
Ok I tried the Latex thing but I couldn't figure it out so i'll just write normally.

For the acceleration I used a = v2 / r = 30.52 / 100 = 9,34.

The second one is the one I'm sure must be wrong but I don't know what else to try. I'm using the equation for kinetic friction fk=\muk*n which should be simply 0.98*900*9.80 =8652.42 = 8.65 kN but that isn't the answer.
 

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