Friction of rubber box on concrete floor

AI Thread Summary
A 10 kg rubber box on a concrete floor experiences a horizontal force of 200 N, prompting a discussion on the friction force acting on it. The maximum static friction force is calculated using the coefficient of friction, which is 1.00 for rubber on concrete, leading to a normal force of 98.1 N. The friction force could be 0 N if the box remains at rest, but with the applied force exceeding static friction, it is likely to slide. Clarification is sought on whether the question pertains to the friction force before or after sliding begins. The consensus indicates that the box will slide, thus the friction force will be equal to the maximum static friction until that point.
anon3005
Messages
1
Reaction score
0

Homework Statement


A 10 kg rubber box is resting on a concrete floor. A force of 200 N is then applied to this box in a horizontal direction. What is the magnitude of the friction force on the box?

Homework Equations


This is a question about applying Newton's laws so Fsmax = μs η and η = mg.

The Attempt at a Solution


I have had answers -200 N, 98.1N, and 200N in which they are all incorrect. I have an idea it could be 0 N since the net force would have to be 0 since it is at rest and there is a static friction present but I am not sure.
 
Physics news on Phys.org
anon3005 said:

Homework Statement


A 10 kg rubber box is resting on a concrete floor. A force of 200 N is then applied to this box in a horizontal direction. What is the magnitude of the friction force on the box?

Homework Equations


This is a question about applying Newton's laws so Fsmax = μs η and η = mg.

The Attempt at a Solution


I have had answers -200 N, 98.1N, and 200N in which they are all incorrect. I have an idea it could be 0 N since the net force would have to be 0 since it is at rest and there is a static friction present but I am not sure.
What is the co-efficient of friction between rubber and concrete? Is that given? If not, I think you should look it up.
 
cnh1995 said:
What is the co-efficient of friction between rubber and concrete? Is that given? If not, I think you should look it up.

It's 1.00
 
anon3005 said:
It's 1.00
So what's the equation?
 
Is the question asking about the friction force before it starts sliding, or after (assuming it slides)?
 
James R said:
Is the question asking about the friction force before it starts sliding, or after (assuming it slides)?
Given the coefficient of friction, it is safe to assume it slides.
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top