- #1

- 23

- 0

a = -12.2m/s2

m = 925 kg

Fn = 9074.25 N

This is what I've figured out. I don't know how to find the coefficient of friction. If I get the coefficient I think I can multiply it by the normal force to get the frictional force.

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- Thread starter drinkingstraw
- Start date

- #1

- 23

- 0

a = -12.2m/s2

m = 925 kg

Fn = 9074.25 N

This is what I've figured out. I don't know how to find the coefficient of friction. If I get the coefficient I think I can multiply it by the normal force to get the frictional force.

- #2

Nabeshin

Science Advisor

- 2,205

- 16

The question asks only for the frictional

- #3

- 327

- 1

F_f = u*F_n

F_n = mg

F_f = u *mg

find u

F_n = mg

F_f = u *mg

find u

- #4

- 18

- 0

The free body diagram is the way to go. Fn and Fg cancel out. What other force or forces provide the acceleration?

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