Frictional Force: Comparing Forces

AI Thread Summary
When pushing a chair across a carpet at a constant velocity of 0.5 m/s, the applied force equals the frictional force, resulting in a net force of zero. If the applied force is increased, it will exceed the kinetic frictional force, causing the chair to accelerate. The coefficient of kinetic friction remains constant regardless of the applied force. The reasoning presented correctly identifies the relationship between applied force and frictional force in both scenarios. Overall, the explanation is accurate and aligns with the principles of physics.
krackers
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Homework Statement



If you push a chair across a carpet at a constant velocity of 0.5 m/s, how does the force you are exerting on that chair compare with the force the force of friction? If you increase the force you are exerting, how does the new frictional force compare with the previous frictional force?

2. The attempt at a solution

Part I. Since there is a constant velocity there should be no acceleration. This means that the net force must be 0. Since there is clearly force applied in one direction, the frictional force oppose the applied force equally, so the frictional force is to the force that you apply to the chair.

Part 2. However, let's say you increase the force applied. Since the coefficient of kinetic friction is a constant, and since you were previously providing just enough force to balance the kinetic frictional force, and the force applied will be greater than the kinetic frictional force. Thus, due to the net force, the object will accelerate.

Is my reasoning correct?
 
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krackers said:

Homework Statement



If you push a chair across a carpet at a constant velocity of 0.5 m/s, how does the force you are exerting on that chair compare with the force the force of friction? If you increase the force you are exerting, how does the new frictional force compare with the previous frictional force?

2. The attempt at a solution

Part I. Since there is a constant velocity there should be no acceleration. This means that the net force must be 0. Since there is clearly force applied in one direction, the frictional force oppose the applied force equally, so the frictional force is to the force that you apply to the chair.

Part 2. However, let's say you increase the force applied. Since the coefficient of kinetic friction is a constant, and since you were previously providing just enough force to balance the kinetic frictional force, and the force applied will be greater than the kinetic frictional force. Thus, due to the net force, the object will accelerate.

Is my reasoning correct?

Yeah, it all sounds fine to me.
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
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