Frictional Forces on a Wooden Crate with External Forces

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The discussion revolves around calculating frictional forces acting on a wooden crate subjected to external forces. For part A, participants express confusion about determining the frictional force when a perpendicular force is applied. In part B, the approach involves equating the frictional force to the applied force, but there is uncertainty about the correct interpretation of variables. Clarifications are sought regarding the relationship between the normal force and the external forces applied. The conversation highlights the complexities in applying static friction equations in this scenario.
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having major issue with this question.

Homework Statement


a wooden crate of mass m= 60 kg sits on the horizontal surface. the coefficient of static friction between the block and the surface is u=0.5 . an external force P = 220 N, is also applied to the block in a direction parallel to the surface. Also an external force F is applied to the block in a direction perpendicular downwards to the surface.
A) if the force F = 40 N, what is the magnitude and direction of the frictional force that the surface exerts on the block?
B) what is the smallest force F, necessary to hold the block stationary on the surface?
upload_2017-6-19_9-35-5.png


variables
m = 60kg
P = 220N
U = 0.5

Homework Equations


equations
Fs<= U*Fn
F = ma
Fn = mg

The Attempt at a Solution


not sure on where to start for part a in this question. but was thinking for part b you let Ff = P so that
Ff<= U*Fn+f
Ff<= U*mg + f
220<= U*mg + f
and then rearrange to solve for f
am i on the right track for part b at least?
 
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braydon said:
Fn = mg
Not always, and not in this case.
braydon said:
Ff<= U*mg + f
Is f the same as the given F?
What you have written means Ff<=(U*mg)+f. Is that what you intended?
 
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