Functions of Two Variables. Need Help

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SUMMARY

The discussion focuses on solving a tutorial question involving functions of two variables, specifically finding partial derivatives and applying the chain rule. The user has successfully derived the partial derivatives as Fx(x,y) = Cos(x) Sin(y) and Fy(x,y) = Sin(x) Cos(y). To find stationary points, they identified conditions where Fx = 0 and Fy = 0, leading to values such as x = 0 or y = π/2. The user seeks clarification on applying the chain rule for two variables in the context of the given problem.

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  • Understanding of partial derivatives in multivariable calculus
  • Familiarity with the chain rule for functions of multiple variables
  • Knowledge of gradient vectors and their geometric interpretation
  • Basic trigonometric functions and their derivatives
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Students and educators in calculus, particularly those focusing on multivariable functions, as well as anyone needing assistance with partial derivatives and the chain rule in mathematical analysis.

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I need some help with one of my tutorial questions. This is the question
http://img122.imageshack.us/img122/9820/ques3dd3.jpg

For Part (a), I have found the partial derivatives as

Fx (x,y) = Cos(x) Sin(y)
Fy (x,y) = Sin(x) Cos (y)

Then to find the stationary points, Let Fx = 0 and Fy = 0. But I am not sure how to find the values..

For Part (b), I have no idea how to solve it..

For Part (c), I know the chain rule for two variables but I am not sure how to apply it to this question. If someone could point out an example that would be great =)

Thx for the help!
 
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(a)Fx = 0 when x = 0 or y = pi/2, or x = pi or y = 3pi/2 etc. as long as you are confined within the domain.

(b) hint: gradient of function is the normal vector of the function surface at a certain point.

chain rule is
dg/dt = (df/dx)(dx/dt) + (df/dy)(dy/dt)

were x = t^2; y = exp(t)

if then f(x,y) is Sin(x) * Sin(y)

we get:

df/dx = Cos(t^2) Sin(exp(t))

and (df/dx)*(dx/dt) = 2tCos(t^2) Sin(exp(t))

similar for (df/dy)(dy/dt)

but I am not so sure about the chain rule anymore.
 
Last edited:

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