Gauge pressure and fluids problem

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Homework Help Overview

The problem involves determining the gauge pressure of an automobile tire as its temperature changes, specifically from 0.64 degrees Celsius to 39 degrees Celsius. The context is within the subject area of thermodynamics and gas laws, particularly focusing on the relationship between pressure and temperature in gases.

Discussion Character

  • Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the use of the equation relating pressure and temperature, with one participant suggesting the ideal gas law. Questions arise regarding the variables in the equations, such as the meaning of "n" and "R" in the ideal gas law.

Discussion Status

The discussion is exploring the relationship between pressure and temperature using relevant equations. Some participants are clarifying concepts and definitions, while others are attempting to connect their prior knowledge to the problem at hand. There is no explicit consensus yet, but guidance has been offered regarding the relevant equations.

Contextual Notes

Participants note that the volume of the gas remains constant and that the atmospheric pressure is assumed to be constant. There is also an indication that some participants may not have learned all the necessary concepts yet.

kitty9035
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1. Homework Statement [/b
An automobile tire having a temperature of .64 degrees C is filled to a gauge pressure of 27 lb ft/in2. What would be the gauge pressure in the tire when its temperature rises to 39 degrees C?

Homework Equations



Assume the volume remains constant, the air doesn't leak out, and the atmospheric pressure remains constant at 14.7 lb ft/in2

The Attempt at a Solution



i'm pretty sure your supposed to use the equation p=pg + po. How do I find the gauge pressure with a temperature increase??
 
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You're right that you have to use that equation, and there is one other, too. What equation do you know that relates the pressure and temperature of a gas?
 
would it be PV=nRT? I didn't learn about this yet. I just looked it up. What does the n and R stand for?
 
That's what I had in mind. If you haven't learned that, maybe you have learned some form of it for the particular case where the volume and amount of gas are constant? Does this look familiar?:
\frac{P_1}{T_1}=\frac{P_2}{T_2}
In this equation P and T are the absolute temperature and pressure, and 1 and 2 refer to different times.

By the way, in the ideal gas law "n" is the number of moles of gas and "R" is the universal gas constant, which is just a constant value.
 
Thank you! I got the answer:smile:
 
LeonhardEuler said:
That's what I had in mind. If you haven't learned that, maybe you have learned some form of it for the particular case where the volume and amount of gas are constant? Does this look familiar?:
\frac{P_1}{T_1}=\frac{P_2}{T_2}
In this equation P and T are the absolute temperature and pressure, and 1 and 2 refer to different times.

By the way, in the ideal gas law "n" is the number of moles of gas and "R" is the universal gas constant, which is just a constant value.
Proportions are always more precise because they are independent of sig figs
 

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