Gauss' Law - Electric Field for a Charged Metal Plate

[Gustavo]

Homework Statement

An infinite metal plate has a surface density of charge σ_L=-6μC/m² , Left side and a surface density Of load σ_R=+4μC/m² , in the right side. A Gaussian surface In the form of a circular cylinder, with area A 12 cm², is Located with the left side inside the plaque and a thin Plate loaded to the right. The surface charge density of the Metal plate is σ_A. Check the correct option with respect to the density value Superficial σ_A And flow Φ_E Through the Gaussian.

ANSWER: D

Homework Equations

Gauss law for an infinite plate: E=|σ|/2ε₀

The Attempt at a Solution

I could not understand the problem, I do not know how to find the density and nor the flow. I tried to use Gauss's Law but I could not understand the problem.

 

[haruspex]

I could not understand the problem,

Can you be more specific about what it is that you do not understand?
You have a charged thick metal plate and a charged thin metal plate. Since the thick plate is a conductor, what can you say about the field inside it?
You quote the formula for the field resulting from an infinite uniform plane of charge. What fields from such planes act inside the thick plate? What equation does that give you?