Gauss' Law: Infinite plane with charge

AI Thread Summary
An infinite plane of charge with a surface charge density of 6.8 µC/m² leads to an electric field calculated as E = 384170.791 N/C. The potential difference of 100 V is used to find the distance between equipotential surfaces using the formula ΔX = ΔV/E, resulting in ΔX = 0.0002603 m. A participant initially miscalculated the conversion to millimeters, stating 2.603 mm instead of the correct 0.2603 mm. The discussion emphasizes the importance of proper unit conversion and significant figures in physics calculations. Ultimately, the correct distance between equipotential surfaces is confirmed to be 0.2603 mm.
SnakeDoc
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Homework Statement


An infinite plane of charge has surface charge density 6.8 µC/m2. How far apart are the equipotential surfaces whose potentials differ by 100 V? In mm

Homework Equations


E=σ/(2ε0)

The Attempt at a Solution


So first I solved for E= 6.8e-6/(2*8.85e-12) = 384170.791

then because ΔV= E *ΔX
so
ΔX=ΔV/E

so then I substituted
ΔX = 100/ 384170.791
ΔX = .0002603

The site says that I've made a power of ten error the answer must be in mm but I'm not sure what I am doing wrong
 
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SnakeDoc said:
ΔX = 100/ 384170.791
ΔX = .0002603

The site says that I've made a power of ten error the answer must be in mm but I'm not sure what I am doing wrong
So far you've expressed your ΔX in meters. What value did you enter for your answer in mm? How many significant figures did you provide?
 
I entered 2.603 mm
 
SnakeDoc said:
I entered 2.603 mm
Numerically the result looks to be good. How many significant figures do the given data support?
 
I realized my mistake its supposed to be .2603mm I converted from Meters to millimeters improperly. Thank you.
 
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