- #1
ilovetswift
- 4
- 0
Homework Statement
Homework Equations
The Attempt at a Solution
I'm not sure if I am doing part a,b,e, and f correctly
Gauss's Law insulating cylinder concentric shell
- Thread starter ilovetswift
- Start date
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- Cylinder Gauss's law Law Shell
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Homework Help Overview
The discussion revolves around applying Gauss's Law to a problem involving an insulating cylinder and a concentric shell. Participants are addressing specific parts of the problem and clarifying their understanding of the variables and equations involved.
Discussion Character
- Mixed
Approaches and Questions Raised
- Participants are questioning the clarity of the original poster's equations and variable definitions. There is uncertainty about the correct interpretation of the problem's parameters, particularly regarding the radius and the effects of the cylinder's length. Some participants suggest that the original poster may have made substitutions that could lead to incorrect conclusions.
Discussion Status
The discussion is ongoing, with participants providing feedback on the clarity of the original poster's work and suggesting improvements for future posts. There is no explicit consensus yet, as various interpretations of the problem are being explored.
Contextual Notes
Participants note issues with the readability of the original poster's attachments, which may hinder understanding. There is also mention of the need to define variables clearly to facilitate better communication.
I'm not sure if I am doing part a,b,e, and f correctly
- #2
- 42,896
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You'd get more responses if you were to post attachments that are the right way up! Even after rotation, the handwritten parts are pretty hard to read.
For a), the denominator is hard to read, but it looks like .1π(.01)2, which would be right.
For b), you seem to have used 'a' in place of the given variable r, and used r as the .01m radius. The cylinder length is ten times the radius, so I would think you are supposed to ignore end effects. If I ignore that term in the denominator and simplify what's left, it seems to give a value which increases with distance from the central cylinder, which cannot be right.
Pls take the trouble to post your working in LaTex, or write very clearly (no still-visible rubbings out!). It would also help if you were to define your variables.
For a), the denominator is hard to read, but it looks like .1π(.01)2, which would be right.
For b), you seem to have used 'a' in place of the given variable r, and used r as the .01m radius. The cylinder length is ten times the radius, so I would think you are supposed to ignore end effects. If I ignore that term in the denominator and simplify what's left, it seems to give a value which increases with distance from the central cylinder, which cannot be right.
Pls take the trouble to post your working in LaTex, or write very clearly (no still-visible rubbings out!). It would also help if you were to define your variables.
- #3
ilovetswift
- 4
- 0
How do you post the attachments that are up right away? Also, on my pc they do not need to be rotated for whatever reason when they uploaded it turned them sorry.
a) i have written .1 pi (.01)^2 in the denominator
Thank you, and dually noted
a) i have written .1 pi (.01)^2 in the denominator
Thank you, and dually noted
- #4
- 42,896
- 10,527
Sorry, I don't know what the magic is there. I've never run into the problem, but I see you're not alone. Some come out 180 degrees out. Sounds like a landscape/portrait mix-up.ilovetswift said:
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