Generators (know r, l, B, angular speed of coil) how to find peak EMF?

AI Thread Summary
To find the peak EMF of a generator with a coil radius of 0.14 m, wire length of 5.7 m, magnetic field strength of 0.20 T, and angular speed of 25 rad/s, the number of loops (N) can be calculated using the formula N = L / (2πr). The area (A) of the coil is determined using A = πr^2. The peak EMF can then be calculated with the formula Emf_peak = ωNBA, which simplifies to Emf_peak = (1/2)ωLrB. This approach allows for the determination of the peak EMF based on the provided parameters.
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The coil of a generator has a radius of 0.14 m. When this coil is unwound, the wire from which it is made has a length of 5.7 m. The magnetic field of the generator is 0.20 T, and the coil rotates at an angular speed of 25 rad/s. What is the peak emf of this generator?

Please help me get started on thsi one :)
 
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i had to do a similar question..
cant remember how i did it though >_<
 
Knowing the wire length and the loop radius you can determine both loop area A and number of loops N.

Given: r = 0.14m, L = 5.7m, B = 0.2T, \omega = 25rad/s

N = \frac{L}{circumference} = \frac{L}{2\pi r}

A = \pi r^2

Emf_{peak} = \omega NBA = \frac{1}{2}\omega LrB.
 
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