Get Expert Help with Basic Integrals | General Formula and Practice Exercises

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stud said:
I need help please with a basic integral.

http://i40.tinypic.com/a589qp.gif

These integrals is immediate?
What the general formula?

And here, exercises 1 & 4:
http://i43.tinypic.com/zksmck.gif

Thanks.

What have you tried?

You have to show work before any help is given. From the FAQ:

1) Did you show your work? Homework helpers will not assist with any questions until you've shown your own effort on the problem. Remember, we help with homework, we don't do your homework. We already passed those classes, it's your turn to do so.
 
hey curious,
can how show my effort to solve this exercise?

i am not know to solve this integral, because i ask help please.
 
stud said:
hey curious,
can how show my effort to solve this exercise?
You can show what you've tried by typing it out step by step, for example:

x2-2=0
x2=2
x= +/- sqrt(2)

or better yet, use Latex!

x^2-2=0
x^2=2
x=\pm\sqrt{2}

These can be written as follows (taking out the spaces in the tex tags)

[ tex]x^2-2=0[ /tex]
[ tex]x^2=2[ /tex]
[ tex]x=\pm\sqrt{2}[ /tex]

For integrals, use

\int{\frac{x}{x^2+1}}

[ tex]\int{\frac{x}{x^2+1}}[ /tex]

If you ever see latex being used and want to know how to type it yourself, you can quote that message and in the quote it will show you the text required.

stud said:
i am not know to solve this integral, because i ask help please.

For the first two, think about using this technique:

\frac{a}{a+b}=\frac{a+b-b}{a+b}=1-\frac{b}{a+b}
 
Mentallic said:
For the first two, think about using this technique:

\frac{a}{a+b}=\frac{a+b-b}{a+b}=1-\frac{b}{a+b}

That was the *exact* hint I was thinking about providing before I decided to wait for TS' reply first and went offline. *Exact*, word for word, same symbols and everything. You ARE a mindreader, Mentalist, oops, Mentallic. :smile:

Stud: This is a very good hint. For the first integral, you get an almost-immediate answer, without needing any substitution. The second integral, you can get an almost-immediate answer for it if you recognise a particular form (hint: derivative of \arctan{x}). If not, you can try a x = \tan\theta substitution on the second term after applying this trick.

Mentallist, I or someone else can hint you along with the rest as well, but you HAVE to show some work here first. Deal? :smile:
 
Last edited:
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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