Given angle and distance traveled find initial velocity

AI Thread Summary
To find the initial velocity of a ball hit at a 45-degree angle that clears a fence 98 meters away, the problem can be broken down into horizontal and vertical components. The horizontal distance equation, Vx*t = 98, and the vertical motion equation, Vsin(45) - (1/2)gt = 0, create a system of two equations with two unknowns. By substituting Vx with Vcos(45) in the first equation, both equations can be simplified to solve for the initial velocity. The approach involves using trigonometric identities and kinematic equations while disregarding air friction. This method effectively allows for the calculation of the ball's initial velocity upon leaving the bat.
shaunk
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A ball is pictched at a batter, the batter hits the ball at a 45 degree angle It just clears the outfield fence 98m away Find velocity of the ball when it left the bat. Assume fence is the same height as the pitch. Disreguarding air friction I can't figure out how to find initial velocity.
 
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How did you approach the problem?
 
I attempted to break the problem down to its components using Vx= Vcos45 and vy=Vsin45 then used the formula Vx=x/t then 0=Vyit = 1/2gt^2
 
shaunk said:
I attempted to break the problem down to its components using Vx= Vcos45 and vy=Vsin45 then used the formula Vx=x/t then 0=Vyit = 1/2gt^2

Looks good to me.

so

Vx*t = 90

Vcos45*t = 90
Vsin45*t - (1/2)gt^2 = 0

you've got 2 equations with 2 unknowns... you can simplify the second equation by dividing by t (since the answer we need is not t = 0)...

Vsin45 - (1/2)gt = 0

so solve:

Vcos45*t = 90
Vsin45 - (1/2)gt = 0
 
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