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Hello,
Ive done the first part of a question which was to derive the equation
\displaystyle{\theta(t) = \theta_0 \sin(\omega_0t + \phi)}
for a pendulum
where \displaystyle{\omega_0 = \sqrt{\frac{g}{r}}} and \displaystyle{\phi = \sin^{-1} \left(\frac{\theta_1}{\theta_0}\right)}
r = \mbox{length of rod (pendulum)}
The next part says
Sketch \theta(t) versus t for the cases \phi = 0 and \displastyle{\phi = \frac{\pi}{2}}
How do I do this if i don't know \theta_0 or r? I know they are both constant though, does this have a bearing on the situation?
Thankyou
Ive done the first part of a question which was to derive the equation
\displaystyle{\theta(t) = \theta_0 \sin(\omega_0t + \phi)}
for a pendulum
where \displaystyle{\omega_0 = \sqrt{\frac{g}{r}}} and \displaystyle{\phi = \sin^{-1} \left(\frac{\theta_1}{\theta_0}\right)}
r = \mbox{length of rod (pendulum)}
The next part says
Sketch \theta(t) versus t for the cases \phi = 0 and \displastyle{\phi = \frac{\pi}{2}}
How do I do this if i don't know \theta_0 or r? I know they are both constant though, does this have a bearing on the situation?
Thankyou
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