Understanding the Thin Lens Equation: How to Graph and Interpret Results

AI Thread Summary
The discussion centers on the correct formulation of the thin lens equation for graphing purposes. One participant questions the validity of the original equation provided, suggesting an alternative that maintains proper unit consistency. Concerns are raised about the feasibility of graphing without knowing specific values for the variables involved. The need for a 3D graph is highlighted if values are unknown, indicating a more complex analysis. Accurate understanding of the equation is crucial for effective graphing and interpretation of results.
Larrytsai
Messages
222
Reaction score
0
I need to learn how to graph do=1/(f -1/di) like i have my measurements and when i plug in my di i get a do so what do i do with my old do?
 
Physics news on Phys.org
Larrytsai said:
do=1/(f -1/di)

Are you sure that's the correct equation? Shouldn't it be the following?

d_o=\frac{fd_i}{d_i-f}
 
Tom Mattson said:
Are you sure that's the correct equation? Shouldn't it be the following?

d_o=\frac{fd_i}{d_i-f}

umm that's the way my teacher wrote it. Iduno he might be wrong lol
 
I don't think you typed it in correctly. In the denominator you have f-1/di. You're subtracting a distance and an inverse distance. The units don't work out. Please check it. Also, when you say you need to graph the equation, do you know the values of any of the variables do, di, or f? If not, then you'll have to do a 3D graph, which is much more involved.
 

Thread 'Struggling to understand the concept of this question (ice cube in water optics question)'

TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
View full post »
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
View full post »

Similar threads

Find the location and length of the final image
Replies
2
Views
887
Graphically determining the focal length of a converging lens
Replies
4
Views
2K
Inserting thick lenses into a thin lens system and deducing values
Replies
1
Views
2K
What is the power of the lens in diopters?
Replies
3
Views
4K
Lens Maker's Formula - Confusion in the derivation
Replies
15
Views
1K
Focal length of the eyepiece lens in a compound microscope
Replies
7
Views
1K
What is the focal length of the lens?
Replies
20
Views
4K
How Do You Calculate the Final Image Position in a Three-Lens System?
Replies
8
Views
6K
Converging lens solve for all variables given f, Hi, and Ho
Replies
3
Views
2K
Microscope converging lens problem
Replies
3
Views
3K

Hot Threads

Recent Insights

Back
Top