Gravitational pull on two objects

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    Gravitational Pull
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Homework Help Overview

The discussion revolves around calculating the net gravitational force acting on one mass (mass A) due to two other masses (masses B and C) in a linear arrangement. The problem involves gravitational interactions and the application of Newton's law of universal gravitation.

Discussion Character

  • Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to apply the gravitational force formula but questions the correctness of their calculations. Participants inquire about the expected result and the reasoning behind the original poster's expectations.

Discussion Status

Participants are actively engaging with the problem, with some offering guidance on the correct application of gravitational formulas. There is an exploration of the original poster's calculations and assumptions, but no consensus has been reached regarding the correct approach.

Contextual Notes

The discussion highlights potential misunderstandings in applying the gravitational force equation and the distances involved in the calculations. The original poster's expectations for the outcome are also noted, indicating a possible miscalculation or misinterpretation of the formula.

enantiomer1
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If three balls (all weighing 2.0kg) are lined in a row, what is the magnitude of the net gravitational force on mass A due to masses B and C in the figure. B is 10cm from A, and C is 50 cm from A (and of course C is 40 cm from B)
(here's a 'diagram')
(A)----(B)----------------------------C
I've been using the equation G*(m1m2/Rsq) and been adding the gravitational pull from a & b and a & c but for some reason that's wrong. So where do I need to fine tune my equation?
 
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What answer do you get? What do you expect to get (i.e., why do you think you are wrong)? Show your work, please.
 
I'm expecting to get 3.00×10-9 due to, the fact that G*(2kg*2kg)/.1m + G*(2kg*2kg)/.5m = 3.00×10-9
 
You aren't using Newton's formula for gravitation. Look the equation, then look at what you are doing.
 

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