Green's Ellipse (Move to Math homework)

Calpalned
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Homework Statement


Picture1.png


Homework Equations


N/A

The Attempt at a Solution


Question 1) Suppose I tried to convert ##\int \int_c {-2y^3} dA## into polar coordinates. What would the limits be? I know that ##x = rcos(\theta), y = rsin(\theta)## but the two rs are different (unlike in a circle).

Q2) Regarding the picture, it says "Notice that this region is symmetric about..."). I was never taught this in school and as a result I have a few questions: Is there a trick for memorizing this? Is there a simple proof? Are there any other examples where I could use this "symmetry trick"? And finally, it seems that the trick is only dependent on ##-2y^3## and not on the shape of the ellipse, right?

Q3) The symm
 
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Calpalned said:
How do I move a thread to another forum?
Taken care of. :wink:

In future, if you need help, just hit the "Report" button in the lower left hand corner and leave a message for a mentor.
 
Calpalned said:

Homework Statement


View attachment 81907

Homework Equations


N/A

The Attempt at a Solution


Question 1) Suppose I tried to convert ##\int \int_c {-2y^3} dA## into polar coordinates. What would the limits be? I know that ##x = rcos(\theta), y = rsin(\theta)## but the two rs are different (unlike in a circle).

An ellipse is a closed curve, like a circle, so if you use the polar form of an ellipse, the coordinates will repeat after a while.

http://en.wikipedia.org/wiki/Ellipse#Polar_form_relative_to_center

It's not clear why you want to convert the integral in the OP to polar coordinates.

Q2) Regarding the picture, it says "Notice that this region is symmetric about..."). I was never taught this in school and as a result I have a few questions: Is there a trick for memorizing this? Is there a simple proof? Are there any other examples where I could use this "symmetry trick"? And finally, it seems that the trick is only dependent on ##-2y^3## and not on the shape of the ellipse, right?

You don't sound like you are familiar with the shape of the conic sections.

You should study these curves as they pop up quite frequently in math & physics:

http://en.wikipedia.org/wiki/Conic_section
 
Calpalned said:

Homework Statement



Question 1) Suppose I tried to convert ##\int \int_c {-2y^3} dA## into polar coordinates. What would the limits be? I know that ##x = rcos(\theta), y = rsin(\theta)## but the two rs are different (unlike in a circle).

Rewrite the ellipse in standard form:$$
\frac {x^2} 2 + \frac{y^2} 1 = 1$$This suggests the polar-like substitution$$
x = \sqrt 2 r \cos\theta,~~y= r \sin\theta$$Now you can let ##r## vary from ##0## to ##1## and ##\theta## from ##0## to ##2\pi##. And don't forget the proper ##dA##.

Q2) Regarding the picture, it says "Notice that this region is symmetric about..."). I was never taught this in school and as a result I have a few questions: Is there a trick for memorizing this? Is there a simple proof? Are there any other examples where I could use this "symmetry trick"? And finally, it seems that the trick is only dependent on ##-2y^3## and not on the shape of the ellipse, right?
Wrong. The shape of the ellipse being symmetric is why the integral is zero with an odd integrand in ##y##.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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