Guage Pressure, force, and displacement help

AI Thread Summary
The discussion revolves around calculating gauge pressure using the formula P = ρgh, where ρ is the density of water, g is gravitational acceleration, and h is the height of the water column. The user is confused about their calculations, believing they should arrive at 1000 N/m². Clarification is provided that the gauge pressure is determined by the depth of the water, and they need to consider both the downward force on the top of the block and the upward force on the bottom to find the net force. The conversation emphasizes understanding the relationship between pressure, force, and displacement in fluid mechanics. The user seeks assistance to correctly approach the problem.
Landlocked26
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If someone could please help with the attached assignment. I am having trouble getting started with this and cannot find a suitable answer online by myself. I am trying to do part A first and then work from there but I feel like I am wrong.

A.
P=rho*g*h
P=1000 kg/m3 * 10 m/s2 * .1m
P=

I am not getting what I am supposed to come up with when I multiply these. I think it is
1000 N/m2.
 

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Landlocked26 said:
If someone could please help with the attached assignment. I am having trouble getting started with this and cannot find a suitable answer online by myself. I am trying to do part A first and then work from there but I feel like I am wrong.

A.
P=rho*g*h
P=1000 kg/m3 * 10 m/s2 * .1m
P=

I am not getting what I am supposed to come up with when I multiply these. I think it is
1000 N/m2.
The gauge pressure is the pressure due to the water. That pressure is a function only of the depth: P = F/A = \rho gh. You have calculated the pressure on the top of the block. What is the pressure on the bottom?

What is the downward force on the top of the block due to water pressure (use pressure x area to find force)? What is the upward force on the bottom? What is the net force? What direction is the net force? (up or down?).

AM
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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