Hard integration problem (calc 2)

Azi
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I've been going at this problem for at least 3 hours :cry:

Just need to find the integral for:

INTEGRAL(x^3e^x^2) / (x^2 + 1)^2 dxI've tried all kinds of different methods, filling up at 4 pages in my notebook! I think this is the closest I've gotten :confused:

First I broke up the numerator so that it's: x^2xe^x^2
Attempting to solve with u-substitution

u = x^2 + 1
x^2 = u - 1
du = 2xdx
1/2du = xdx

1/2INTEGRAL((u-1)e^(u-1)) / (u^2) du

And I don't know what to do from here, I don't feel like I'm on the right track. If anyone has a tip it would be much appreciated!
 
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Try letting u = x2; that way you don't have to work with (u - 1)eu - 1 and you get euu.
 
Hmm yeah that probably is the best choice, I tried it earlier but am still hitting a wall

u = x^2
du = 2xdx
1/2du = xdx

1/2INTEGRAL (Ue^U) / (U+1)^2 dU

Can that be integrated? I've always been so bad at knowing when I can do something and when I can't, it kills me on tests.
 
Looks like your only option now is integration by parts, seems like no other kinds of substitutions would help. You only have a few things to try with u, eu, and 1/(u + 1)2, shouldn't be too hard.
 
Thanks! I think I may have gotten it, not 100% sure though, got class soon so i'll find out then. Thanks again
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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