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Hard integration problem (calc 2)

  1. Jul 14, 2010 #1

    Azi

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    I've been going at this problem for at least 3 hours :cry:

    Just need to find the integral for:

    INTEGRAL(x^3e^x^2) / (x^2 + 1)^2 dx


    I've tried all kinds of different methods, filling up at 4 pages in my notebook! I think this is the closest I've gotten :confused:

    First I broke up the numerator so that it's: x^2xe^x^2
    Attempting to solve with u-substitution

    u = x^2 + 1
    x^2 = u - 1
    du = 2xdx
    1/2du = xdx

    1/2INTEGRAL((u-1)e^(u-1)) / (u^2) du

    And I don't know what to do from here, I don't feel like I'm on the right track. If anyone has a tip it would be much appreciated!
     
    Last edited: Jul 14, 2010
  2. jcsd
  3. Jul 14, 2010 #2
    Try letting u = x2; that way you don't have to work with (u - 1)eu - 1 and you get euu.
     
  4. Jul 14, 2010 #3

    Azi

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    Hmm yeah that probably is the best choice, I tried it earlier but am still hitting a wall

    u = x^2
    du = 2xdx
    1/2du = xdx

    1/2INTEGRAL (Ue^U) / (U+1)^2 dU

    Can that be integrated? I've always been so bad at knowing when I can do something and when I can't, it kills me on tests.
     
  5. Jul 14, 2010 #4
    Looks like your only option now is integration by parts, seems like no other kinds of substitutions would help. You only have a few things to try with u, eu, and 1/(u + 1)2, shouldn't be too hard.
     
  6. Jul 14, 2010 #5

    Azi

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    Thanks! I think I may have gotten it, not 100% sure though, got class soon so i'll find out then. Thanks again
     
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