Harmonic oscillator momentum distribution

andresordonez
Messages
65
Reaction score
0
Hi, I don't understand why the momentum probability distribution of the quantum mechanical oscillator has the same shape as the position probability distribution (with peaks at the extremes), I mean, I understand the mathematics but I don't understand the concept.

This is my reasoning (which I'm sure is wrong, but I don't see why)

The position probability distribution has peaks (for high energies) approximately at the positions corresponding to the amplitude of the classical oscillator. The physical explanation of this, is that the oscillator spends more time in the extreme positions because there its velocity is close to zero.

But then what this means is that if I measured (classically) many times the position of the oscillator (at a fixed energy) I would get that most of the measurements would have the oscillator in the extreme positions (where the momentum would be close to zero) right?

How come then, that if I measure many times the momentum I get most of the measurements with a high momentum?? (in other words, that the momentum probability distribution has peaks at the extremes)

Thanks
 
Last edited:
Physics news on Phys.org
Well, this is what happens:

When the oscillator is near the extreme positions, the momentum changes rapidly (the acceleration is maximum at the extreme positions) and the momentum measurements are distributed over a wide range, that is, while the position changes slowly, the momentum changes rapidly, so if you have, say, 3 consecutive measurements of the position near the extremes, you would get the first measurement of the momentum (corresponding to the first measurement of the position) far from zero, the 2nd measurement close to zero, and the third far from zero again. The opposite would be true when the position is close to zero. It's kinda hard to visualize (at least it was for me), so I'll attach a plot where it can be seen clearly.

The vertical bars correspond to a measurement, and I considered \pm[1,.9] to be near the extremes and [-.1,.1] to be near zero.

The purple line corresponds to the position and the blue line to the momentum.
 

Attachments

  • harmonicOscillator.jpg
    harmonicOscillator.jpg
    23.9 KB · Views: 587
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top