Heat flow through aluminium rod

AI Thread Summary
The discussion centers on calculating heat flow through a solid aluminum rod with a diameter of 40mm and a length of 750mm, given a temperature difference of 100°C. The thermal conductivity of aluminum is provided as 235 Wm-1K-1. The user initially miscalculates the cross-sectional area, mistakenly using the total surface area formula instead of the correct area for a solid cylinder. After clarification, it is confirmed that the cross-sectional area should be calculated using the formula for a circle, leading to the correct approach for solving the problem. The conversation concludes with the user expressing gratitude for the clarification.
em3
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Homework Statement


An Aluminium rod has a diameter of 40mm. and is 750mm long. If the temperature difference between the ends of the rod is 100C .

Take the thermal conductivity of Aluminium to be 235 Wm-1K-1

Homework Equations


k * A * ΔT / L

The Attempt at a Solution


235 * 0.097 m * 100 / 0.75

The answer is supposed to be 39.4 Js-1 but I can't get it right? So I don't know if I'm doing something wrong, and I've tried so many times. I don't know what I'm doing wrong.
Thanks
 
Last edited:
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Hi em3,

Welcome to Physics Forums!

em3 said:
235 * 0.095 m * 100 / 0.75
How did you arrive at 0.095 m for the cross sectional area?
 
40mm. and is 750mm into m, 0.04m and 0.75m. Then did A=2πrL+2πr2

2 * ∏ * 0.02 * 0.75 + 2∏0.022≈ 0.097
Sorry, made a typo in first post
 
em3 said:
40mm. and is 750mm into m, 0.04m and 0.75m. Then did A=2πrL+2πr2
You want the cross sectional area, not the total surface area.
 
How do I find that? The question only gives me the diameter and length, no inner or outer diameter.
 
em3 said:
How do I find that? The question only gives me the diameter and length, no inner or outer diameter.
Assume that a rod is a solid cylinder.
 
Oh ok thanks, I got it. Thanks a lot!
 
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