You have to use partial fraction integration which involves splitting the integral into terms that are easier to integrate. After pulling an "x" from the bottom of the original integral you get INT (x+1)/x(x+2)
After splitting and such:
x + 1 = A(x+2) + Bx
Plugging in clever values for x we will get that A & B both equal 1/2
Substituting back into our original problem we will have the INT of .5/x + .5/(x+2) which will yield an answer of 0.5 ln|x| + 0.5 ln|x+2|
I'm assuming you know how to use partial fraction integration. If not, respond back and i'll try helping you further.
You've been taught partial fractions but not u-substitution?
In any case, let u=x2+2x
Then du/dx=2x+2 and du=2(x+1)dx
Substitute u and du back into the integral accordingly - remember that there is no 2 in the integral so you'll need to make it du/2=(x+1)dx. Now it's simple to integrate (and don't forget to substitute u=x2+2x back into your answer!)
#7
IntegrateMe
214
1
^_^
It's strange having an "x" in your "u-value" but i guess that way is easier. Thanks :)