[SOLVED] Hitting a baseball 1. The problem statement, all variables and given/known data A batter hits a pitched ball when the center of the ball is 1.37 m above the ground.The ball leaves the bat at an angle of 45° with the ground. With that launch, the ball should have a horizontal range (returning to the launch level) of 106 m. (a) Does the ball clear a 8.40-m-high fence that is 96.0 m horizontally from the launch point? (b) At the fence, what is the distance between the fence top and the ball center? 2. Relevant equations 3. The attempt at a solution So for v0 I get sqrt(9.8*106/1) = 32.38209382 So to find out when its over the fence I do 96/t*cos(45) = 4.192579478 So I then plug this into y = y0+(v0*sin(45))t - 1/2 g(t^2) = 11.23915888 which means it clears the fence but, This minus 8.4 = 2.84 but its saying that this answer is incorrect. Anyone see where I'm going wrong?