Horizontal and Vertical Velocity

AI Thread Summary
A rookie quarterback throws a football with an initial upward velocity of 16.5 m/s and a horizontal velocity of 18.3 m/s, with air resistance ignored. The time to reach the highest point of the trajectory is correctly calculated as 1.68 seconds. To find the maximum height, the vertical component should be used instead of the horizontal component in the displacement formula. The correct formula is s = 16.5(1.68) + ½(-9.8)(1.68)². This clarification helps resolve the confusion regarding the calculation of the football's maximum height.
kgianqu2
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A rookie quarterback throws a football with an initial upward velocity component of 16.5 and a horizontal velocity component of 18.3 . Ignore air resistance.

A)How much time is required for the football to reach the highest point of the trajectory?

I got 1.68s which is correct

B) How high is this point?

I can't get the right answer. I got 16.9m by doing: 0m+18.3(1.68)+1/2(-9.8)(1.68)2

Help please!
 
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kgianqu2 said:
A rookie quarterback throws a football with an initial upward velocity component of 16.5 and a horizontal velocity component of 18.3 . Ignore air resistance.

A)How much time is required for the football to reach the highest point of the trajectory?

I got 1.68s which is correct

B) How high is this point?

I can't get the right answer. I got 16.9m by doing: 0m+18.3(1.68)+1/2(-9.8)(1.68)2

Help please!

b) To determine the max height of the projectile, you only need to use the vertical components. You incorrectly used the horizontal component for the displacement formula. It should be...

s = 16.5(1.68) + ½(-9.8)(1.68)²
 
Thank you!
 

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