Horizontal and Vertical Velocity

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SUMMARY

The discussion focuses on the physics of projectile motion, specifically analyzing the trajectory of a football thrown by a rookie quarterback with an initial upward velocity of 16.5 m/s and a horizontal velocity of 18.3 m/s. The time to reach the highest point of the trajectory is confirmed to be 1.68 seconds. The correct formula for calculating the maximum height is identified as s = 16.5(1.68) + ½(-9.8)(1.68)², correcting the initial misapplication of the horizontal component in the displacement formula.

PREREQUISITES
  • Understanding of projectile motion principles
  • Familiarity with kinematic equations
  • Knowledge of vertical and horizontal velocity components
  • Basic grasp of gravitational acceleration (9.8 m/s²)
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  • Study kinematic equations for projectile motion
  • Learn about the effects of air resistance on projectile trajectories
  • Explore advanced projectile motion scenarios involving varying angles
  • Investigate real-world applications of projectile motion in sports
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Students studying physics, educators teaching projectile motion concepts, and sports analysts evaluating throwing techniques in football.

kgianqu2
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A rookie quarterback throws a football with an initial upward velocity component of 16.5 and a horizontal velocity component of 18.3 . Ignore air resistance.

A)How much time is required for the football to reach the highest point of the trajectory?

I got 1.68s which is correct

B) How high is this point?

I can't get the right answer. I got 16.9m by doing: 0m+18.3(1.68)+1/2(-9.8)(1.68)2

Help please!
 
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kgianqu2 said:
A rookie quarterback throws a football with an initial upward velocity component of 16.5 and a horizontal velocity component of 18.3 . Ignore air resistance.

A)How much time is required for the football to reach the highest point of the trajectory?

I got 1.68s which is correct

B) How high is this point?

I can't get the right answer. I got 16.9m by doing: 0m+18.3(1.68)+1/2(-9.8)(1.68)2

Help please!

b) To determine the max height of the projectile, you only need to use the vertical components. You incorrectly used the horizontal component for the displacement formula. It should be...

s = 16.5(1.68) + ½(-9.8)(1.68)²
 
Thank you!
 

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