How are these vector equations equivalent?

  • Thread starter Thread starter Calpalned
  • Start date Start date
  • Tags Tags
    Vector Writing
Calpalned
Messages
297
Reaction score
6

Homework Statement


My solutions manual states that (1 - t)(2i - j + 4k) + t(4i + 6j + k) = (2i - j + 4k) + t(2i + 7j -3k), 0 < t < 1.

Homework Equations


r(t) = (1 - t)r0 + tr1

The Attempt at a Solution


I don't see how they are equivalent. They can't be divided because one has i, j and k and the other has t.
 
Physics news on Phys.org
Try simplifying the left side and see what you get
 
What they wrote is just the summation of the two vectors, component-by-component. Which part don't you understand?

Chet
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top