How Can You Identify Diffraction Gratings Using a Laser and Detection Screen?

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To identify the diffraction gratings, shine a red laser on each grating and observe the interference patterns on a detection screen. The grating with 10,000 lines/cm will produce a narrower angular spread for its maxima compared to the 5,000 lines/cm grating due to the higher line density. Calculating the angles for the first maximum using the formula nλ = d sin(θ) reveals that the first maximum for the 5,000 line grating occurs at approximately 0.029 radians, while for the 10,000 line grating, it occurs at about 0.057 radians. The distance between the central maximum and subsequent maxima can be calculated based on these angles and the distance to the screen. The distinct angular positions of the maxima will help in determining which grating has the higher line density.
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You find two unlabelled diffraction gratings in your lab. From purchase records, you know that one grating has 5000 lines/cm, while the other has 10 000 lines/cm. Given the following equipment, describe how you would determine which is the grating with 10 000 lines/cm:
• Red laser
• detection screen
• the two unknown diffraction gratings
describe what difference you would observe.
n = d sin(theta)
d=1/5*105 = 2*10-6
d=1/1*106= 10-6
I don’t know how to start can someone give me any idea about this question
 
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At what angle would you see the first maximum for the 5000 line grating? At what angle would you see the first maximum for the 10000 line grating?

If you had a screen, say, 10 m away from the 5000 line grating, how far would the central maximum be from the first, second and nth maximas? What about for the 10000 line grating?
 
You missed a \lambda in your equation. It should read

n \lambda = d sin(\theta)

Anyway, what do you expect the difference between the interference patterns to be when you shine the laser on the two different gratings? Where is the first order (n=1) maximum with each grating?Edit:
And I see oedipa maas just posted similar remarks. . .
 
Last edited:
thats what i got
suppose the wavelength= 1cm = 1*10^-9
and m= 1
when d= 2*10^-6 m/line
theta= 0.029

when d= 10^-6
theta= 0.057
that's all what i got
 
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