How Can You Solve the Integral of x sqrt(x/(x-1)) Without a Trig Substitution?

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Homework Statement


integral of x *sqrt( x/(x-1))


Homework Equations





The Attempt at a Solution


I honestly don't know how to approach this i don't see any type of trig substituions whatsover, I really need some kind of lead and an explnation y that method works
 
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Sidthewall said:

Homework Statement


integral of x *sqrt( x/(x-1))


Homework Equations





The Attempt at a Solution


I honestly don't know how to approach this i don't see any type of trig substituions whatsover, I really need some kind of lead and an explnation y that method works

Hmmm... I guess I'd start by making the substitution u=\frac{x}{x-1}=1+\frac{1}{x-1} in order to get rid of the junk inside the square root. You'll probably find that doing this will allow you to split the integral into two easier integrals since x=1+\frac{1}{u-1}
 
Sidthewall said:

Homework Statement


integral of x *sqrt( x/(x-1))


Homework Equations





The Attempt at a Solution


I honestly don't know how to approach this i don't see any type of trig substituions whatsover, I really need some kind of lead and an explnation y that method works

I haven't carried this all the way through, but I think it will work
\int x \sqrt{\frac{x}{x - 1}}dx = \int \frac{x^{3/2}}{\sqrt{x - 1}}dx

I believe that an ordinary substitution will work.
Let u = sqrt(x - 1).
 
You can integrate secn θ using integration by parts, letting u=secn-2 θ and dv=sec2 θ dθ. For sec5 θ, you'll have to do it twice. It's a bit tedious but straightforward.
 
You don't actually need a trig sub. You can also use Partial Fraction Decomposition if you find that easier.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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